Question

The perimeter of a rectangle is 78 feet. The length of the rectangle is twice the width. Find the length and width of the rectangle.

Answer 1

Given:

Perimeter of rectangle is 78 feet

Let the width of the rectangle be w

Then the length of the rectangle be 2w

Now, the perimeter is given by the formula:

`P=2(l+b)`

Substitute l= 2w and b=w

`\begin{gathered} P=2(2w+w) \\ =2(3w) \\ =6w \end{gathered}`

Given perimeter = 78 feet so,

`\begin{gathered} P=6w \\ 78=6w \\ w=(78)/(6) \\ w=13 \end{gathered}`

Hence, the width of rectangle is 13 feet

The length of rectangle is 2w= 2(13)=26 feet.