Answer
Step-by-step explanation
Background
• Diameter: ,line that touches two opposite points in a circumference and passes through the center of the circle.
,
• Radius: ,the distance from the center to any point in the circumference. Also, it is half the diameter.
The surface area (SA) of a cylinder is given by:
![SA=2\pi r^2+2\pi rh](https://img.qammunity.org/2023/formulas/mathematics/college/w2jlqmcfop109pz0fl1flof4inguq1n7to.png)
where r represents the radius and h represents the height.
Based on the given figures, we can conclude that:
• The cylinder in the upper left corner has a diameter of 12 and a height of 8, meaning r = 12/2 = 6 and h = 8.
• The cylinder in the upper right corner has a radius of 2 and a height of 12, meaning r = 2 and h = 12.
• The cylinder in the lower right corner has a radius of 7 and a height of 5, meaning r = 7 and h = 5.
• The cylinder in the lower left corner has a diameter of 8 and a height of 17, meaning r = 8/2 = 4 and h = 17.
Now, we can replace these values in the formula:
• Cylinder in the upper left corner
![SA=2\pi(6)^2+2\pi(6)(8)](https://img.qammunity.org/2023/formulas/mathematics/college/fpsd38avso37nmig5c57t3txaa9d2770r9.png)
![SA=2\pi(36)+2\pi(48)](https://img.qammunity.org/2023/formulas/mathematics/college/rl541qgx5woec0ayrl9digkl1va43f8tn2.png)
![SA=72\pi+96\pi](https://img.qammunity.org/2023/formulas/mathematics/college/9s1vme853zesqucal14yfnnmzf4o4kpkug.png)
![SA=168\pi\approx527.78\approx528](https://img.qammunity.org/2023/formulas/mathematics/college/tbspjxyj9ah49e93jmpx4m1yz3h2tzngdw.png)
• Cylinder in the upper right corner
![SA=2\pi(2)^2+2\pi(2)(12)](https://img.qammunity.org/2023/formulas/mathematics/college/lk0qhx955dctxq40etc977ar4egyyhs1vm.png)
![SA=8\pi+48\pi=56\pi](https://img.qammunity.org/2023/formulas/mathematics/college/peovms1r7iwmfcqrhaagf3f0n3ghnnql96.png)
![SA=56\pi\approx175.93\approx176](https://img.qammunity.org/2023/formulas/mathematics/college/jrhv8ws6vjgz48ow4smfmr1qbltif8ak3s.png)
• Cylinder in the lower right corner
![SA=2\pi(7)^2+2\pi(7)(5)](https://img.qammunity.org/2023/formulas/mathematics/college/n8hyvgyjgx5n5o93vhikrc7chxe6ep6zvp.png)
![SA=98\pi+70\pi=168\pi\approx528](https://img.qammunity.org/2023/formulas/mathematics/college/alnyr12kml8jev4yovn43g5uc87xp1nes1.png)
• Cylinder in the lower left corner
![SA=2\pi(4)^2+2\pi(4)(17)](https://img.qammunity.org/2023/formulas/mathematics/college/v3bi5ynh0v7kypdd27kvmv75b3ifdhux26.png)
![SA=32\pi+1362\pi=168\pi\approx528](https://img.qammunity.org/2023/formulas/mathematics/college/4yzpewtd40zqk0ukmv69woj0cg9b1i3d7g.png)