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Find the perimeter and area of the sector for the figure shown in white, to three significant figures.

Find the perimeter and area of the sector for the figure shown in white, to three-example-1

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The area of a circle is computed as follows:


A=\pi\cdot r^2

If the radius is 7 cm, then the area is:


A=\pi\cdot7^2=153.938\text{ sq. cm}

If the radius is 5 cm, then the area is:


A=\pi\cdot5^2=78.539\text{ sq. cm}

Then, the area of the "ring" made by the subtraction of a circle of a radius of 5 cm to a circle of a radius of 7 cm is:

153.938 - 78.539 = 75.399 sq. cm

In the picture of the problem, we see a part of this "ring". The whole area computed before corresponds to an angle of 360°, to calculate the area that corresponds to 120° we can use the next proportion:


\begin{gathered} \frac{75.399\text{ sq. cm}}{x\text{ sq. cm}}=\frac{360\text{ \degree}}{120\text{ \degree}} \\ (75.399)/(x)=3 \\ (75.399)/(3)=x \\ 25.133\text{ sq. cm= x} \end{gathered}

The perimeter of a circle is computed as follows:


P=2\cdot\pi\cdot r

If the radius is 7 cm, then the perimeter is:


P=2\cdot\pi\cdot7=43.982\text{ cm}

Given that 120° is 1/3 of a circle, then the length of the top arc is:

1/3*43.982 = 14.66 cm

If the radius is 5 cm, then the perimeter is:


P=2\cdot\pi\cdot5=31.415\text{ cm}

Given that 120° is 1/3 of a circle, then the length of the bottom arc is:

1/3*31.415 = 10.471 cm

Then, the perimeter of the figure is:

14.66 + 10.471 + 2 + 2 = 29.131 cm

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