Given:
sin θ = 5/13
θ is in Quadrant II
Find: sec θ and tan θ
Solution:
Recall that the sine function follows the pattern:
![sin\theta=(opposite)/(hypotenuse)=(y)/(r)](https://img.qammunity.org/2023/formulas/mathematics/college/4id6a8tpj5lrbvjcgn58yl7l1mbviscoug.png)
Therefore, from the given sin value, y = 5 and r = 13. Since the angle is found in quadrant II, the value of y is positive while the value of x should be negative.
Now, let's solve for the value of x using the formula below.
![x=√(r^2-y^2)](https://img.qammunity.org/2023/formulas/mathematics/college/nczhzh2a8cxjo7lr8p6e4cojuxtxf77nyt.png)