since the transverse axis is parallel to the x - axis . we will use :
(x-h)^2 /a^2 - (y-k)^2 / b^2 = 1 , where ( h,k) : ( -3; 2 )
and a = semi congugate axis /2 = 8/2 = 4
and b = semi transverve axis /2 = 12/2 = 6
lets substitute :
( x-h/a)^2 - (y-k/b)^2 = 1
( x- (-3) / 4) - ( y - 2)/6)^2 = 1
((x+3)/4))^2 - (( y-2) /6)^2 = 1
(x+3)^2 / 16 - (y-2)^2 / 36 = 1
This means choose option number 2 for the first box answer, and
choose option number 4 for the second box .