Question

Follow the instructions below.5 2Writer ·x without exponents.+00.05 2X - XХ$Fių in the blank.52. X = X

Answer 1

x · x · x · x · x · x · x

5+2

Given:

`x^5\cdot x^2`

We can expand this as:

`\begin{gathered} x^5=x\cdot x\cdot x\cdot x\cdot x \\ x^2=x\cdot x \\ \end{gathered}`

Therefore:

`\begin{gathered} x^5\cdot x^2=(x\cdot x\cdot x\cdot x\cdot x)\cdot(x\cdot x) \\ =x\cdot x\cdot x\cdot x\cdot x\cdot x\cdot x \end{gathered}`

Now, according to the Product Rule of Exponents:

`a^x* a^y=a^(x+y)`

Applying this to our expression:

`x^5\cdot x^2=x^(5+2)`