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User SeDav
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We can assume that the levels of carbon dioxide in 1959 are the 100% of all the emissions. Then, if in 2005 the figure was 395 parts per million, we have that the increase is:


\begin{gathered} (395\cdot100)/(339)=(39500)/(339)=116.52 \\ \Rightarrow116.52-100=16.52 \end{gathered}

therefore, the percent increase was of 16.52%

Next, we have the following:


339(16.52\%)=339(0.1652)=56

thus, the increase in carbon dioxide levels is 56 parts per million

User Jakoss
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