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Determine if the graph is symmetric above the x-axis the y-axis or the originr=-5-5costheta

Determine if the graph is symmetric above the x-axis the y-axis or the originr=-5-5costheta-example-1
User AAudibert
by
6.8k points

1 Answer

3 votes

Step 1: Test for symmetry about the x-axis by Replacing θ with -θ in the equation

The curve r=f(θ) is symmetrical about the x-axis if the equation r=f(θ) is unchanged by replacing θ with -θ


r=5-5\cos (-\theta)=5-5\cos \theta\text{ (}\cos (-\theta)=\cos \theta)

Hence, the curve is symmetrical about the x-axis

Step 2 Test for symmetry about the y-axis by Replacing θ with -θ and r with -r in the equation

The curve r=f(θ) is symmetrical about the x-axis if the equation r=f(θ) is unchanged by replacing θ

with -θ and r with -r


\begin{gathered} -r=5-5\cos (-\theta)=5-5\cos \theta \\ \text{ Therefore} \\ r=-5+5\cos \theta \\ \text{ Since } \\ -5+5\cos \theta\\e5-5\cos \theta \\ \text{ then there is no symmetry about the y-axis} \end{gathered}

Step 2 Test for symmetry about the origin by replacing r with -r in the equation

The curve r=f(θ) is symmetrical about the origin if the equation r=f(θ) is unchanged by replacing r

with -r


\begin{gathered} -r=5-5\cos \theta \\ \text{this implies that} \\ r=-5+5\cos \theta \\ \text{ Since} \\ -5+5\cos \theta\\e5-5\cos \theta \\ \text{ then there is no symmetry about the origin} \end{gathered}

Therefore, the curve is symmetrical only about the x-axis.

Hence, the right option is the first one.

User Flame Of Udun
by
6.9k points
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