Question

What is the average angular acceleration during this time interval.

Answer 1

`3.07876rad\/s^2`

Step-by-step explanation

To find the average angular acceleration, we have to find the difference in the angular speeds and divide it by time:

`\alpha=(\omega_2-\omega_1)/(t)`

Therefore, the angular acceleration is:

`\begin{gathered} \alpha=(8.5\pi-3.6\pi)/(5) \\ \alpha=(4.9\pi)/(5) \\ \alpha=3.07876rad\/s^2 \end{gathered}`