Question

24 square root of 2 ,45 degrees find x

Answer 1

Let's use cos identity:

`\begin{gathered} \cos (\theta)=\frac{adjacent}{\text{hypotenuse}} \\ So\colon \\ \cos (45)=\frac{x}{24\sqrt[]{2}} \\ \text{Solving for x:} \\ (24\sqrt[]{2})\cdot\cos (45)=x \\ x=24^(\circ) \end{gathered}`