Question

A baseball manager is determining the batting order for the team.The team has 9 players,but the manager definitely wants the pitcher to bat last.How many batting orders are possible.

Answer 1

Step 1:

In this question, we are given the following:

A baseball manager is determining the batting order for the team.

The team has 9 players, but the manager definitely wants the pitcher to bat last. How many batting orders are possible.

Step 2:

The details of the solution are as follows:

Since the pitcher bats last, there is only one choice for the 9th slot.

For the 1st slot, there are 8 choices remaining.

For the 2nd slot, there are 7 choices remaining, etc.

So the number of possible batting orders is:

`8\text{ x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 8}!=\text{ 40320 orders}`