Question

Please help me I'm struggling very muchSolve using a GCFx^3+14x^2+48x=0

Answer 1

The given expression is,

`x^3+14x^2+48x=0`

Reordering the terms, we get,

`48x+14x^2+x^3=0`

Here, the GCF is x, therefore, we have,

`\begin{gathered} x(48+14x+x^2)=0 \\ x((x+6)(x+8))=0 \end{gathered}`

Equating each term to zero, we get,

`\begin{gathered} x=0 \\ x=-6 \\ x=-8 \end{gathered}`

Thus the solution is x = 0, -6, -8