Question

11:20 Mathematics 5 points Graph the line that passes through the points (3, -6) and (-6, -3) and determine he equation of the line. timswife · Helping Handcan you show me how to graphthis

Answer 1

The slope of the line that passes through the points (x1, y1) and (x2, y2) is computed as follows:

`m=(y_2-y_1)/(x_2-x_1)`

The line passes through the points (3, -6) and (-6, -3), its slope is:

`m=(-3-(-6))/(-6-3)=(3)/(-9)=-(1)/(3)`

The slope-intercept form of a line is:

y = mx + b

where m is the slope and b is the y-intercept.

Substituting with m = -1/3 and the point (3, -6), we get:

`\begin{gathered} -6=-(1)/(3)\cdot3+b \\ -6=-1+b \\ -6+1=b \\ -5=b \end{gathered}`

The equation is:

y = -1/3x - 5

To graph a line, you need to find 2 points on it and connect them. Using the points (3, -6) and (-6, -3), we get: