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How many moles of NaF are in 34.2 grams of a 45.5% by mass NaF solution?

How many moles of NaF are in 34.2 grams of a 45.5% by mass NaF solution?-example-1

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"45.5% by mass NaF solution" means that 45.5% of the mass of the solution is NaF.

The solution has 34.2g of mass, so 45.5% of this is the mass of NaF:


_{}m_(NaF)=34.2g\cdot0.455=15.561g

To transform this into moles, we need the molar mass of NaF, which we can calculate using the atomic masses of Na and F:


M_(NaF)=M_(Na)+M_F\approx22.9897g/mol+18.9984g/mol=41.9881g/mol

So, the number of moles is:


M_(NaF)=(m_(NaF))/(n_(NaF))=(15.561g)/(41.9881g/mol)\approx0.371mol

So, there are approximately 0.371 mol of NaF.

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