Question

Complete and balance the molecular equation, including the phases, for the reaction of aqueous potassium sulfate, K2SO4, and aqueous strontium iodide, SrI2. Molecular equation: K2SO4(aq) + SrI2(aq) → 2KI(aq) + SrSO4(s) Write the balanced net ionic equation, including the phases, for this reaction. Net ionic equation:

Answer 1

Answer;

`SO^(2-)_4(aq)+Sr^(2+)(aq)\rightarrow SrSO_4(s)`

Explanations:

An ionic equation is a chemical equation in which the electrolytes in aqueous solution are expressed as dissociated ions.

Given the molecular equation of the reaction of aqueous potassium sulfate, K2SO4, and aqueous strontium iodide, SrI2 as shown:

`K_2SO_4\mleft(aq\mright)+SrI_2\mleft(aq\mright)\to2KI\mleft(aq\mright)+SrSO_4\mleft(s\mright)`

The total ionic equation is as shown below;

`2K^++SO^(2-)_4+Sr^(2+)+2I^-\rightarrow2K^++2I^-_{^{^{}}}+SrSO_4`

Next is to get the net ionic equation from the total ionic equation. Canceling out the common ions on both sides of the equation will give:

`\begin{gathered} \cancel{2K^{+_{}}}^{}+SO^(2-)_4+Sr^(2+)+\cancel{2I^-}\rightarrow\cancel{2K^+}+\cancel{2I^-}^{}_{^{^{}}}+SrSO_4 \\ SO^(2-)_4(aq)+Sr^(2+)(aq)\rightarrow SrSO_4(s) \end{gathered}`

This gives the net ionic equation of the given molecular equation