The given information is:
- There are 3 children
- Each of the children will be allowed to select one box from the 10 different boxes of cereal available
- All the boxes are different
The number of ways the boxes can be selected n= 10!=10x9x8x7x6x5x4x3x2x1
The number of ways the 3 children can choose r= 3!=3x2x1
Here we have a permutation without repetition, because we have to reduce the options each time, so the formula is:
![P=(n!)/((n-r)!)](https://img.qammunity.org/2023/formulas/mathematics/high-school/m6bem3f0fl350db11jl56i21ppsfb0tv1u.png)
If we replace n=10 and r=3, we obtain:
![P=(10!)/((10-3)!)=(10!)/(7!)=(10*9*8*7*6*5*4*3*2*1)/(7*6*5*4*3*2*1)=10*9*8=720](https://img.qammunity.org/2023/formulas/mathematics/college/yluq12c9lrg8zvjk6ami3v81ns57wsjjw8.png)
The answer is 720.