Question

In a lab, you burned a piece of Mg and experimentally produced 4.80 g of MgO according to the given reaction. The theoretical yield is 5.30 g of MgO. What is your percent yield?2Mg + O2 → 2MgO

Answer 1

Let's see the formula of percent yield:

`\text{Percent yield=}\frac{actual\text{ yield}}{theoretical\text{ yield}}\cdot100.`

Our actual yield is what we got from the reaction, which is 4.80 g and the theoretical yield is 5.30 g, so replacing these values in the formula we're going to obtain:

`\begin{gathered} \text{Percent yield=}(4.80g)/(5.30g)\cdot100, \\ \text{Percent yield}=90.566\%. \end{gathered}`

The percent yield of MgO is 90.566%.