Question

2) Find the equation of the line passing through the points (1, -2) and (2, 4). Write the equatior slope-intercept form. OY=2x-4 y = -22 y= 6x - 8 y = -6x + 4 Si Premious Next docx

Answer 1

The slope of a line that passes through points (x1, y1) and (x2, y2) is:

`m=(y_2-y_1)/(x_2-x_1)`

Replacing with the points (1, -2) and (2, 4),

`m=(4-(-2))/(2-1)=(6)/(1)=6`

The slope-intercept form of a line is:

y = mx + b

where m is the slope and b is the t-intercept

Replacing with point (1, -2) and m = 6:

-2 = 6(1) + b

-2 = 6 + b

-2 - 6 = b

-8 = b

Then, the equation is:

y = 6x - 8