Question

How would you prepare 1.5L of 3.0M sulfuric acid from 16.0M stock solution?

Answer 1

These solutions that are made from stock solutions, follow the next steps:

Step 1

Formula used:

`M1\text{ x V1 = M2 x V2 \lparen1\rparen}`

Where,

M1 = concentration of stock solution

V1 = volume of the stock solution

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M2 = concentration of new solution

V2 = volume of new solution

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Step 2

These kinds of solutions are prepared with sulfuric acid and water as a solvent.

Information provided:

M1 = 16.0 M

V1 = unknown

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M2 = 3.0 M

V2 = 1.5 L

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Step 3

Procedure:

From (1),

V1 = M2 x V2/M1

V1 = (3.0 M x 1.5 L)/16.0 M = 0.28 L of stock solution

Answer:

How would you prepare the new solution?

0.28 L of stock solution are taken. Next, 1.22 L of water is added to the 0.28 L to complete 1.5 L of the new solution. Finally, the new solution (1.5 L and 3.0 M) is ready to be used.