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Given f(x)= x3 - 2x2 - X + 2,the roots of f(x) areDONE1, -2, -1, 21-1, 1, 21-1, 1, -2-1,1, -2,01-1, 1, 2,0

User Tejas Rao
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1 Answer

4 votes

Given data:


f(x)=x^3-2x^2-x+2

To find the roots ,


x^3-2x^2-x+2=0^{}

Now, by using long division method


(x^3-2x-x+2)/(x-1)=x^2-x-2

Solving further,


\begin{gathered} x^2-x-2=0 \\ x^2-2x+x-2=0 \\ x(x-2)+1(x-2)=0_{} \\ (x+1)(x-2)=0 \end{gathered}
\begin{gathered} x+1=0 \\ x-2=0 \end{gathered}

Thus, the roots of the polynomial are 2 , -1 , 1

The correct option is (2)

User Amitdatta
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8.0k points

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