47.3k views
2 votes
The admission fee at an amusement park is $3.25 for children and $4.80 for adults. On a certain day, 284 people entered the park, and the admission fees collected totaled $1109. How many children and how many adults were admitted?

1 Answer

4 votes

Given: The admission fee at an amusement park is $3.25 for children and $4.80 for adults

To Determine: How many children and how many adults were admitted if the total money collected is $1109

Solution

Let x be number of children and y be the number of adults

So,


\begin{gathered} equation1:x+y=284 \\ equation2:3.25x+4.80y=1109 \end{gathered}

Solve for x and y


\begin{gathered} from\text{ equation 1} \\ equation3:x=284-y \end{gathered}

Substitute x in equation 2


\begin{gathered} 3.25(284-y)+4.80y=1109 \\ 923-3.25y+4.80y=1109 \\ 923+1.55y=1109 \end{gathered}
\begin{gathered} 1.55y=1109-923 \\ 1.55y=186 \\ y=(186)/(1.55) \\ y=120 \end{gathered}

Substitute y in equation 3


\begin{gathered} x=284-y \\ x=284-120 \\ x=164 \end{gathered}

Hence, there are 164 children and 120 adults

User Goba
by
7.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories