Question

What is the equation of the line that goes through (8,-2) and (0,14

Answer 1

Let,

`\begin{gathered} (x_1,y_1)=(8,-2) \\ (x_2,y_2)=(0,14) \end{gathered}`

The expression to calculate the equation of a straight line passing through two given points is,

`(y-y_1)/(y_2-y_1)=(x-x_1)/(x_2-x_1)`

Substitute values in the above expression.

`\begin{gathered} (y-(-2))/(14-(-2))=(x-8)/(0-8) \\ (y+2)/(14+2)=(x-8)/(-8) \\ (y+2)/(16)=(8-x)/(8) \\ y+2=(16)/(8)(8-x) \\ y+2=2(8-x) \\ y=2*8-2x+2 \\ y=16-2x+2 \\ y=18-2x \end{gathered}`

Thus, the expression of the line passing through the given points (8,-2) and (0,14) is 'y=18-2x'.