Question

8. For each pair, insert < > or = between the quantities to make a true comparison, 64 9/4 25(8) 9(2)

Answer 1

`\begin{gathered} a) \\ \sqrt[3]{-8}=-2 \\ \text{and }\sqrt[3]{-64}=-4 \\ \text{But } \\ -2>-4 \\ \sqrt[3]{-8}>\sqrt[3]{-64} \end{gathered}`
`\begin{gathered} (b) \\ 4\sqrt[]{9}=4*3=12 \\ 9\sqrt[]{4}=9*2=18 \\ \text{ Since } \\ 12<18 \\ \text{then} \\ 4\sqrt[]{9}<9\sqrt[]{4} \end{gathered}`
`\begin{gathered} (c) \\ .25(8)=2 \\ 9(.2)=1.8 \\ \text{ Since} \\ 2>1.8 \\ \text{then} \\ .25(8)>9(.2) \end{gathered}`