Answer:
The graph is concave down.
y-intercept: (0, 6)
(i). x = -3 and x = 2.
Step-by-step explanation:
Plotting the function gives us information about the x- and the y-intercepts.
(ii). The x - intercepts of f(x) are solutions to

The above equation is a quadratic equation, and therefore, can be solve using the quadratic formula.
Now, the quadratic formula says that if we have a quadratic equation of the form

the solution is given by
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://img.qammunity.org/2023/formulas/mathematics/college/rxvf73usjbbwyik14knxdemoz21vfz2ufc.png)
Now in our case, we have

Therefore, for the quadratic formula, we have a = -1, b = -1, and c = 6; therefore,
![x=\frac{-(-1)_{}\pm\sqrt[]{(-1)^2-4(-1)(6)}}{2(-1)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ebqy9l5gelthktb25jveeju1o1l8cqr1bu.png)
![\Rightarrow x=\frac{1_{}\pm\sqrt[]{25}}{-2}](https://img.qammunity.org/2023/formulas/mathematics/high-school/zvccupq6g2htk4bjqpunvulab89ebdhyjd.png)


Therefore, we see that the solutions to our quadratic equation ( and therefore, the x-intercepts of f(x)) are x = 2 and x = -3.