Question

Triangle EFG will he rotated 180° clockwise about the origin. What will be the coordinates of the image point E? Point E: (-2,-2)

Answer 1

E=(-2,-2) = (x,y)

x' = xcos(180) + ysin(180)= -2*(-1)+-2*(0) = 2

y' = -xsin(180)+ ycos(180) = -(-2)*(0) + (-2)*(-1)= 2

E' = (2,2)