Question

Find four consecutive integers whose sum is 110

Answer 1

The four integers are: 26, 27, 28 and 29.

Step-by-step explanation:

We want to find four consecutive integers whose sum is 110.

Let these integers be:

m, m+1, m+2, and m+3

Since their sum is 110, we have:

m+(m+1)+(m+2)+(m+3) = 110

Collecting like terms above, we have:

4m + 6 = 110

Subtract 6 from both sides

4m = 110 - 6

4m = 104

Divide both sides by 4

m = 104/4

m = 26

Since we have now gotten a value for m, it is easy to find what the four consecutive integers are.

The integers, like earlier stated are:

m = 26

m+1 = 27

m+2 = 28

and

m+3 = 29.