First we need to find the slope
(-3, 13) and (0, 8)
![\text{slope =}(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/college/6sxzbzc5l5zd4j9mbpevrw2bpisvyhstr6.png)
x₁ = -3 y₁=13 x₂=0 y₂=8
![\text{slope =}(8-13)/(0+3)](https://img.qammunity.org/2023/formulas/mathematics/college/ixrqlqjk846feup77oajx34i2on773gfk4.png)
![\text{slope =}(-5)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/f0ztbx6chg6hb4t6md5eyf816lk2kqc6t5.png)
Next, find the intercept
x=0 y=8 and m = -5/3
substitute into y=mx+ b and solve for b
8 = -5/3(0) + b
b = 8
Substitute m =-5/3 and b = 8 into y=mx+ b
![y\text{ = -}(5)/(3)x\text{ + 8}](https://img.qammunity.org/2023/formulas/mathematics/college/v5hr7bzgdow6zn9499l6kp2wi49t9e3lno.png)
The correct option is option 4)