The formula to find the power is
![P=(W)/(t)](https://img.qammunity.org/2023/formulas/physics/college/4qsgpmv2fzm7zar8pn1q3gnisiytre4iej.png)
Where W represents the work done, which is the product between the force exerted and the distance traveled, W=Fd. In this case, the force is the weight of the student.
![F=mg](https://img.qammunity.org/2023/formulas/physics/college/x86s3sliv7jc1mzs9dn288p05klel6sw3t.png)
Let's replace the mass and the gravity, knowing that 125 pounds are equal to 56.7kg.
![\begin{gathered} F=56.7\operatorname{kg}\cdot9.81m/s^2 \\ F=556.23N \end{gathered}]()
Once we have the force, we can find the work done
![\begin{gathered} W=556.23N\cdot4m \\ W=2,224.92J \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/zse37tnfx8klkkxy509z3r3t22uyq4m3dt.png)
Now we can use the work done to find the power in Watts
![\begin{gathered} P=(2,224.92J)/(5\sec ) \\ P=444.98W \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/lcqdewujs8d12jhxxzw9h055yqckz70qz7.png)
Therefore, the power in Watts is 444.98.