The composite figure is made by: 2 right triangles and 1 semicircle. Or 1 triangle and 1 semicircle. With any of the two combinations of shapes the area is the same.
To find the area you sum the area of each shape that compose the figure:
1 triangle and 1 semicircle:
![\begin{gathered} A=A_(\Delta)+A_s \\ \\ A=(1)/(2)b\cdot h+(1)/(2)\pi\cdot r^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/j28dgua6do46mlhskpwcn6t4mh2yatmr0b.png)
As the given figure has the diameter of the circle you find the radius as follow:
![\begin{gathered} r=(d)/(2) \\ r=(14m)/(2) \\ r=7m \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/prbywe85cla3kpm837f60luse5mcra3dya.png)
The base of the triangle is 14m and the height is 10m.
![\begin{gathered} A=(1)/(2)(14m)(10m)+(1)/(2)\pi(7m)^2 \\ \\ A=(140)/(2)m^2+(49\pi)/(2)m^2 \\ \\ A=70m^2+76.97m^2 \\ \\ A=146.97m^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/dyyx6rzdtqa6c9f1xhwkd3jyo38wab2s9i.png)
The area of the composite figure is 146.97 square meters