Question

A car traveling at 13.6 meters per second crashes into a barrier and stops in 0.321 meters. How many times the weight of the child is this force? Answer must be in 3 significant digits.

Answer 1

Given data

*The given speed of the cacr is u = 13.6 m/s

*The given distance is s = 0.321 m

*The given mass of the child is m = 21.2 kg

*The value of the acceleration due to gravity is g = 9.8 m/s^2

The weight of the child is calculated as

`\begin{gathered} w=mg \\ =21.2*9.8 \\ =207.76\text{ N} \end{gathered}`

As the value of the force is calculated in part (b) is 6110 N

The ratio of the force to the weight of the child is calculated as

`\begin{gathered} (F)/(w)=(6110)/(207.76) \\ F=29.40* w \end{gathered}`