To solve for pH.
Given: the concentration = 1x10^-2 M
[OH-] = NaOH = 1x10^-2 M
kw = [OH-] x [H3O+] = 10^-14
[H3O+] = 10^-14/1x10^-2
[H3O+] = 1x10^-12 M
pH = -log[H3O+]
pH = -log [1x10^-12]
pH = 12
The answer is D.
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