A train accelerates at 2.2 m/s^2. With an initial velocity of 22 m/s, what will be the velocity of the train after 19 s

Jackson Egan asked Nov 19, 2022

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Jackson Egan asked Nov 19, 2022

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16 votes

$a=2.2[(m)/(s^2)]\\v_0=22[(m)/(s)]\\t=19[s]\\\\a = (\Delta v)/(t)\\\Delta v=at=41.8[(m)/(s)]\\v = v_0+\Delta v=63.8[(m)/(s)]$

Answer: The velocity will be 63.8 m/s.

Jarek C answered Nov 23, 2022

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