Question

What is the midpoint of the horizontal line segment graphed below?10(-6,3)(10,3)10A. (2,6)В. (4, 6)ОООC. (2, 3)D. (4, 3)

Answer 1

`(x_m,y_m)=((x_1+x_2)/(2),(y_1+y_2)/(2))`

Therefore,

(-6, 3)(10, 3)

`\begin{gathered} (x_m,y_m)=((-6+10)/(2),(3+3)/(2)) \\ (x_m,y_m)=((4)/(2),(6)/(2)) \\ (x_m,y_m)=(2,3) \end{gathered}`