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State Rolle’s theorem. Using Rolle’s theorem, find a point on the curve

f(x) = cos2x where the tangent is parallel to x-axis on [−π, π].

User Ronnefeldt
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Rolle's theorem:

If a function
f is continuous on the closed interval
[a, b] and differentiable on the open interval
(a,b) such that
f(a) = f(b), then [tex)f′(x) = 0[/tex] for some
x with
a \leq x \leq b.

Tangent:

A tangent is parallel to the x-axis if the slope of the tangent is 0. So, using Rolle's theorem, if we consider
x=-\pi/2 and
x=\pi/2, then
f(-\pi/2)=f(\pi/2)=-1.

Since
f(x) is continuous on
[-\pi/2, \pi/2] and differentiable on
(-\pi/2, \pi/2),
f'(x)=0 for some
-\pi/2 \leq x \leq \pi/2, and thus there is a point in this interval which is parallel to the x-axis.

User Kenroy
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