Question

Solve the equation. 3+[t+4]=10A: [-3,11]B:[-11,3]C: [3,11]D: [-3,-11]

Answer 1

`\begin{gathered} 3+|t+4|=10 \\ |t+4|=10-3 \\ |t+4|=7 \\ now,\text{ we have 2 cases:} \\ 1)\text{ t+4=7 } \\ 2)t+4=-7 \end{gathered}`
`\begin{gathered} In\text{ the first case:} \\ t=7-4\Rightarrow t=3 \\ In\text{ the second one:} \\ t=-7-4\Rightarrow t=-11 \\ \text{hence, } \\ t=3\text{ and t=-11} \end{gathered}`