1 Answer

Nestor · Answer 1 · 2023-07-23T22:58:01+0000

We have a rectangular prism.

It has two equal faces at the front and the back, with dimensions 150 x 80 mm.

It has two equal faces (right and left) with dimensions 150 x 70 mm.

Finally, we have the base and the bottom with dimensions 80 x 70 mm.

We can calculate the area of the front (or back) face as:

$A_(ff)=150mm\cdot80mm=12000mm^2$

We can now calculate the area of the left (or right) face as:

$A_(lf)=150mm\cdot70mm=10500mm^2$

Now, the area of the base is:

$A_b=80mm\cdot70mm=5600m^2$

We can calculate the volume as the product of the lenghts in the three dimensions (length, width and height).

Then, in this case, the volume of the prism is:

$\begin{gathered} V=80mm\cdot70mm\cdot150mm \\ V=840000mm^3 \end{gathered}$

NOTE: We can also calculate the volume as the area of any face times the other dimension that is not part of the face.

For example, we can calculate the volume as the product of the area of the base, 5600 mm², and the height, 150 mm:

$V=A_b\cdot h=5600mm^2\cdot150mm=840000mm^3$

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