Step-by-step explanation:
First, let's rewrite the balanced equation here:
Fe2O3 + 3 H2 --> 2 Fe + 3 H2O
The equation tells us that 3 moles of H2 reacts with 1 mole of Fe2O3 producing 2 moles of Fe and 3 moles of H2O.
We have 12.66 g of H2.
Let's transform it to moles using the following formula:
n = m/MM
MM of H2 = 2 g/mol
n = 12.66/2
n = 6.33 moles
So:
3 moles of H2 ---- 2 moles of Fe
6.33 moles of H2 ---- x moles of Fe
3x = 12.66
x = 12.66/3
x = 4.22 moles of Fe
Now let's transform moles of Fe into grams:
m = n*MM
MM of Fe = 55.845 g/mol
m = 4.22*55.845
m = 235.67 g
Answer: 235.67 g of Iron