Question

Solve the following polynomial equation by grouping and factoring. 9y3−16y=0 Enter the exact answers. The field below accepts a list of numbers or formulas separated by semicolons (e.g. 2;4;6 or x+1;x−1 ). The order of the list does not matter.

Answer 1

Given:

The equation

`9y^3-16y=0`

Required:

Solve by factoring.

Step-by-step explanation:

The steps are:

`\begin{gathered} 9y^3-16y=0 \\ \text{ Take }y\text{ common}, \\ y(9y^2-16)=0 \\ \text{ Use }a^2-b^2=(a-b)(a+b) \\ y((3y)^2-4^2)=0 \\ y(3y-4)(3y+4)=0 \\ y=0,(4)/(3),-(4)/(3) \end{gathered}`

Answer:

`\text{ The solution is }y=0;(4)/(3);-(4)/(3)`