Question

Find the minimum first quartile median third quartile and maximum of the data sey

Answer 1

Minimum = 49

Median = 52

1st quartile = (49+51+51+52 ) /4

. Lower part = 203/4 = 50.75

3rd quartile = (52+53+55+67)/4

Upper part= 217/4 = 54.25

Now find maximum

Maximum M = 67