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A jar contains 23 blue 6 black and 24 yellow marbles a marble is drawn at random p( yellow or blue)

User Ubalo
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1 Answer

3 votes

Solution:

Given;


n(blue)=23,n(black)=6,n(yellow)=24,n(total)=53

Thu;


\begin{gathered} P(yellow\text{ or }blue)=P(yellow)+P(blue) \\ \\ P(yellow\text{ or }blue)=(24)/(53)+(23)/(53) \\ \\ P(yellow\text{ or }blue)=(47)/(53) \end{gathered}

ANSWER:


(47)/(53)

User Everlyne
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