We would apply the relativistic kinetic energy formula which is expressed as
KE = (y - 1)mc^2 = [1/√(1 - v^2/c^2 - 1]mc^2
where
m is the mass of proton
c is the speed of light
v is the speed of the proton
From the information given,
m = 1.67 x 10^-27 kg
c = 3 x 10^8 m/s
v = 0.54c
Thus,
KE = 1.67 x 10^-27 x (3 x 10^8)^2[1/√(1 - (0.54c/c)^2 - 1]
KE = 28.27 x 10^-12 J
We would convert from joules to mev
1 J = 6,241,509,343,260 MeV
28.27 x 10^-12 = 28.27 x 10^-12 x 6,241,509,343,260
KE = 176.48 Mev
the translational kinetic energy is 176.48 Mev