Question

1 Graph a line with a slope of that 4 contains the point (6,3). Ty 6 4 2 х -6 2 4 6 -4 -6

Answer 1

To solve the exercise you can use the point-slope formula, that is,

`\begin{gathered} y-y_1=m(x-x_1) \\ \text{ Where m is the slope of the line and} \\ (x_1,y_1)\text{ is a point through which the line passes} \end{gathered}`

So, in this case, you have

`\begin{gathered} m=(1)/(4) \\ (x_1,y_1)=(6,3) \end{gathered}`
`\begin{gathered} y-y_1=m(x-x_1) \\ \text{ Replace} \\ y-3_{}=(1)/(4)(x-6_{}) \\ y-3_{}=(1)/(4)x-(1)/(4)\cdot6_{} \\ \end{gathered}`