Solution:
Assuming you are rolling a standard 6-sided die with sides numbered 1 to 6, then there are 6 possible outcomes:
![\lbrace1,2,3,4,5,6\rbrace](https://img.qammunity.org/2023/formulas/mathematics/college/axi7whondxcxpddmmvymwk1rt8n0c6fpme.png)
now, note that 4 of these outcomes are greater than 2:
![\lbrace3,4,5,6\rbrace](https://img.qammunity.org/2023/formulas/mathematics/college/s5j48ts5md1ss26mjybw39lt21mzaentww.png)
So the probability of a roll greater than 2 is 4 out of 6, that is:
![P(roll\text{ }>\text{ 2 ) =}(4)/(6)=(2)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/wsj2imu0izyusar4sgyt52d7uoepz9o20q.png)
so that, the correct answer is:
![(2)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/zeht2hdwlb899wfchg7j67j4mj43o3xc1c.png)