Question:
Solution:
Remember the following formula for the distance of an object:
![v\text{ = }(x)/(t)](https://img.qammunity.org/2023/formulas/mathematics/college/xtm6kp54y5130annxa89mgbu8wezivzvui.png)
where x is the distance, t is the time and v is the rate (velocity). Now, from the above equation, we can solve it for distance x:
![x\text{ = v. t}](https://img.qammunity.org/2023/formulas/mathematics/college/su9bike3wv23kjwfp5bhjef3xsbrt3r953.png)
So replacing the data of each option we obtain the distance traveled:
First option:
![x\text{ = 53.2 x 7.74 = 411.76}\approx411.8\\e\text{ 400}](https://img.qammunity.org/2023/formulas/mathematics/college/hw6k2iq5hcmhsbqbgvf2uqtz0tx9gp14qo.png)
then the first option is discarded: the answer is NO.
Second option:
![x\text{ =39.8 x 10.15 = 403.9}\approx404\\e\text{ 400}](https://img.qammunity.org/2023/formulas/mathematics/college/hj9d5p6ysmfzhakaqo4xgve2vvd5btwzg8.png)
then the second option is discarded: the answer is NO.
Third option:
![x\text{ =47.6 x 9.8 = 466.48}\approx466.5\\e\text{ 400}](https://img.qammunity.org/2023/formulas/mathematics/college/upxnukyiz4on8785hadzwz7dxi94ly8xa0.png)
then the third option is discarded: the answer is NO.
Fourth option:
![x\text{ =76.3 x 5.24 = 399.8}\approx400=\text{ 400}](https://img.qammunity.org/2023/formulas/mathematics/college/tkk9qwnehymustxzzb8m1bivbqajxtc8ie.png)
then the fourth option match. Then, the answer is YES.