Given that the pressure applied, p(a), varies inversely to the contact area, a, then these variables are related by the next formula:
![p(a)=(k)/(a)](https://img.qammunity.org/2023/formulas/mathematics/college/esbyuzcb3ah2kpff2e3f7omzx2nsteyn1w.png)
where k is a constant.
Substituting with p(a) = 16 and a = 6 (units are ommited), we get:
![\begin{gathered} 16=(k)/(6) \\ \text{ Isolating k:} \\ 16\cdot6=k \\ 96=k \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/356ak0glknfea3zgd55q80ltlrk1uat2fl.png)
Substituting k = 96 in the formula:
![p(a)=(96)/(a)](https://img.qammunity.org/2023/formulas/mathematics/college/19ddarms7jf4b2cstuy28x9ytvlfojzufv.png)