in this question, we will equal the total distance to be travelled by the runners to the same for a fair race.
calculate the path distance for the runner who will run in inside path/ track.
so for path 1 the total distance is,
![D_1=2(\pi r_1+100)+x+d](https://img.qammunity.org/2023/formulas/mathematics/college/r3474s1cvv3g1fmxbvvbhptyz5vnxje7s7.png)
here the r1 is the radius that is 45m and d is the distance between the finish line and the starting block 1.
Now, we will calculate for the outside track,
![D_2=2(\pi r_2+100)+d](https://img.qammunity.org/2023/formulas/mathematics/college/shyx97fhb02dl8xbd893bsiru6x60b0j7o.png)
here, r2 is 50 m.
for the fair race, D1 and D2 should be equal to each other,
equate both,
![\begin{gathered} D_1=D_2 \\ 2(\pi r_1+100)+x+d=2(\pi r_2+100)+d \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ldn45czlxxgplewjdx7k2ga7kq52dt8h52.png)
put the values and solve further,
![\begin{gathered} 2\pi*45+200+x=2\pi*50+200 \\ x=2\pi(50-45) \\ x=2\pi*5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/aji0af1s1a7crzg4pzk6hfjnq0705y64c2.png)
x=2*3.14*5
x=31.4 m
So, the value of x should be 31.4 m for a fair race.