Question

Suppose you ask a friend to randomly choose an integer between 1 and 10, inclusive.What is the probability that the number will be more than 2 or odd? (Enter your probability as a fraction.)

Answer 1

9/10

Step-by-step explanation:

To determine the probability that the number will be more than 2 or odd, we find the numbers greater than 2 and the numbers that are odd between 1 to 10 inclusive:

Numbers greater than 2 = (3, 4, 5, 6, 7, 8, 9, 10)

Numbers that are odd = (1, 3, 5, 7, 9)

Numbers greater than 2 or odd = (1, 3, 4, 5, 6, 7, 8, 9, 10)

`Pr\text{ (greater than 2 or odd) = }\frac{numbers\text{ greater than 2 or odd)}}{\text{total numbers}}`
`\begin{gathered} we\text{ count the numbers from }\mleft(1,3,4,5,6,7,8,9,10\mright)\text{ = 9} \\ \text{Total numbers = 10} \\ Pr(\text{greater than 2 or odd) = }(9)/(10) \end{gathered}`