we have
Part h
m(x+2)=y-1
this is the equation of a line in point slope form
y-y1=m(x-x1)
where
in this problem
the slope is m
the point is (-2,1)
Find the intercepts
y-intercept is the value of y when the value of x is zero
so
For x=0
m(0+2)=y-1
y-1=2m
y=2m+1
the y-intercept is the point (0,2m+1)
Find the x-intercept (value of x when the value of y is zero)
For y=0
m(x+2)=0-1
m(x+2)=-1
x+2=-(1/m)
x=-(1/m)-2
x-intercept is (-(1/m)-2,0)
Part g
we have
Ax+By=0
equation of the line in standard form
the slope is equal to
m=-A/B
Find the intercepts
y-intercept
For x=0
By=0
y=0
the y-intercept is (0,0)
Find the x-intercept
For y=0
Ax=0
x=0
the x-intercept is (0,0)
that means ----> the line passes through the origin