Question

Find the area of the shaded piece. Round the nearest HUNDREDTH, if needed. AC = 30 and m

Answer 1

`A_(shaded)=(275\pi)/(4)\approx215.98449u²\approx216u²`

1) Considering the line segment AC to be the diameter, then we can state the following:

Assuming point E is in the center of the circle.

2) So now, let's find the area of these identical sectors:

`\begin{gathered} A=(55)/(360)\cdot\pi\cdot15^2 \\ A=(275)/(8)\pi \\ A_(Shaded)=(275)/(8)\pi+(275)/(8)\pi=(275)/(4)\pi \end{gathered}`