Answer:
• (a)1320.5 thousand per year
,
• (b)f(x)=1320.5x+10602
,
• (c)f(7)=19846 thousand
Step-by-step explanation:
Sales in the year 2009 = 10,602 thousand
Sales in the year 2013 = 15,884 thousand.
(a)Average rate of change (slope) from 2009 to 2013.

(b)If x is the number of years since 2009 and f(x) is the number of vehicles sold
When x=0, f(x)=10,602 thousand
The slope-intercept form of the equation of a line is: y=mx+b

The equation of the line through these two points is:

(c)Number of vehicles sold in 2016.
2016-2009=7
Therefore, when x=7
The number of vehicles sold, f(x) will be:
